How far from the left wall did it bounce?
A hard-level "Length" problem.For a bounce, reflect and straighten. Turning a bent path into a straight one is a powerful move.
GivenA table 12 m wide. A ball is hit from A, 3 m up the left wall, bounces once off the bottom wall, and hits B, 6 m up the right wall.
Hints
- When it bounces, the angle coming in equals the angle going out. But we do not know what that angle is, so this alone will not give us a length.
- Here is the move: treat the bottom wall as a mirror and reflect A across it. Call the reflected point A′ — it sits the same 3 m from the wall, but below.
- Reflection keeps lengths and angles, so A′-to-bounce is exactly as long as A-to-bounce. The ball's path has simply been copied to the other side of the wall.
- And here is the payoff: because the two angles are equal, A′ → bounce → B is perfectly straight. The bent path has turned into an ordinary straight line.
- Now it is just similar triangles. From A′ to B the line rises 3 + 6 = 9 m while running 12 m across. The bounce happens after 3 m of that rise, so across it is 12 × 3 ÷ 9.
Answer 4m
More "Length" problems
- a + b + c = ?
- What is the side of the square?
- How long is MN?
- How long is the rope?
- How long is the pole's shadow?
- How deep was the water?