Area of the shaded triangle?

A hard-level "Area" problem.One median halves it, three medians sixth it — always, whatever the triangle's shape.

GivenTriangle ABC has area 48 cm². Each vertex is joined to the midpoint of the opposite side

Hints

Draw just one of them: A to the midpoint of BC. The two halves of BC are equal and the apex A is shared, so the heights are equal too.
Equal bases and equal heights mean equal areas: this line cuts the triangle exactly in half, 48 ÷ 2 = 24 cm² each.
The same holds for all three lines. Drawing all of them cuts the triangle into six pieces, and all three pass through a single point.
Look at any two neighbours: same base length, shared apex, so neighbours always have equal areas. Going right round, all six must be the same size.
Six equal pieces, so one of them is a sixth of the whole: 48 ÷ 6

Answer 8cm²